Botic Van De Zandschulp defeated Alex De Minaur in the Round of 64 at the US Open. The match ended with a score of 6-4, 7-5, 6-2 in favor of Van De Zandschulp. He hit 7 aces and committed 3 double faults, converting 43% of break points and securing 3 service breaks to De Minaur's 1.
Generated automatically from Umpiry match data.
Van De Zandschulp B. took it in straight sets, with five breaks of serve.
Break of serve
Van De Zandschulp B. and De Minaur A. faced 10 of the same opponents in the last 12 months. Van De Zandschulp B. went 4–6 (40%) against them, De Minaur A. 10–4 (71%). De Minaur A. came out better against 5 of 9 comparable opponents, Van De Zandschulp B. against 2 — though 1 of those edges carries caveats (retirement).
Botic Van De Zandschulp beat Alex De Minaur 6-4 7-5 6-2. Umpiry, "Botic Van De Zandschulp vs Alex De Minaur — US Open Round of 64", https://umpiry.com/match/2026-09-04/minaur-vs-zandschulp-us-open-r64?utm_source=cite (as of 4 September 2026).