Andrey Rublev defeated Tallon Griekspoor in the Round of 32 of the Beijing hard-court tournament, winning 6-4, 5-7, 7-6. The match saw Rublev and Griekspoor produce identical totals of 19 aces, while Rublev committed 2 double faults to Griekspoor's 4. Both players converted 1 service break apiece, with Rublev winning 81% of his first-serve points to Griekspoor's 77%.
Generated automatically from Umpiry match data.
Rublev A. came through in three sets, with one break of serve.
Break of serve
Griekspoor T. and Rublev A. faced 7 of the same opponents in the last 12 months. Griekspoor T. went 2–6 (25%) against them, Rublev A. 2–6 (25%). Results against comparable opponents are close (0 : 2 better-results split).
Hard: Rublev A. leads 2–1 · Clay: Rublev A. leads 1–0 · Grass: Rublev A. leads 1–0
Andrey Rublev beat Tallon Griekspoor 4-6 7-5 6-7(6). Umpiry, "Tallon Griekspoor vs Andrey Rublev — Beijing Round of 32", https://umpiry.com/match/2026-10-01/griekspoor-vs-rublev-beijing-r32?utm_source=cite (as of 1 October 2026).