Alexander Zverev advanced to the US Open semifinals with a quarterfinal victory over Botic Van De Zandschulp, winning in straight sets 6-2, 7-5, 6-1. Zverev converted 75 percent of his break points and secured three service breaks to Van De Zandschulp's zero. In the match, Zverev hit six aces and six double faults, while Van De Zandschulp had four aces and one double fault.
Generated automatically from Umpiry match data.
Zverev A. took it in straight sets, with six breaks of serve.
Break of serve
Zverev A. and Van De Zandschulp B. faced 14 of the same opponents in the last 12 months. Zverev A. went 15–8 (65%) against them, Van De Zandschulp B. 7–9 (44%). Zverev A. came out better against 6 of 13 comparable opponents, Van De Zandschulp B. against 4.
Alexander Zverev beat Botic Van De Zandschulp 6-2 7-5 6-1. Umpiry, "Alexander Zverev vs Botic Van De Zandschulp — US Open Quarter-final", https://umpiry.com/match/2026-09-10/zandschulp-vs-zverev-us-open-qf?utm_source=cite (as of 10 September 2026).