Alexander Zverev defeated Quentin Halys in the Round of 64 at the US Open. The match lasted five sets, with Zverev ultimately prevailing 6-4, 4-6, 7-6, 6-7, 6-3. Zverev served 25 aces to Halys' 15 and committed 6 double faults to Halys' 11; both players converted 3 service breaks, but at different conversion rates.
Generated automatically from Umpiry match data.
Zverev A. came through in five sets.
Break of serve
Zverev A. and Halys Q. faced 9 of the same opponents in the last 12 months. Zverev A. went 8–2 (80%) against them, Halys Q. 4–5 (44%). Zverev A. came out better against 3 of 8 comparable opponents, Halys Q. against 0.
Hard: Zverev A. leads 2–0 · Clay: Zverev A. leads 1–0
Alexander Zverev beat Quentin Halys 6-4 4-6 7-6(3) 6-7(3) 6-3. Umpiry, "Alexander Zverev vs Quentin Halys — US Open Round of 64", https://umpiry.com/match/2026-09-04/halys-vs-zverev-us-open-r64?utm_source=cite (as of 4 September 2026).