Alexander Zverev defeated Valentin Royer in the Round of 64 at Wimbledon. The match ended with a score of 6-1, 6-3, 7-6 in favor of Zverev. Zverev hit 14 aces to Royer's 3 and had a first-serve win percentage of 85 compared to Royer's 55.
Generated automatically from Umpiry match data.
Zverev A. took it in straight sets, with five breaks of serve.
Break of serve
Royer V. and Zverev A. faced 8 of the same opponents in the last 12 months. Royer V. went 3–6 (33%) against them, Zverev A. 7–3 (70%). Zverev A. came out better against 3 of 6 comparable opponents, Royer V. against 0 — though 1 of those edges carries caveats (retirement).
Grass: Zverev A. leads 1–0 · Hard: Zverev A. leads 1–0
Alexander Zverev beat Valentin Royer 1-6 3-6 6-7. Umpiry, "Valentin Royer vs Alexander Zverev — Wimbledon Round of 64", https://umpiry.com/match/2026-07-02/royer-vs-zverev-wimbledon-r64?utm_source=cite (as of 2 July 2026).