Jeffrey Von Der Schulenburg: Ranking, Schedule & Stats
- ATP Rank
- #929
- Age
- 24
- Height
- 183 cm (6'0")
- Plays
- Right
Jeffrey Von Der Schulenburg is a professional tennis player from Switzerland, born 13 February 2002. The Swiss competes on the ATP Tour and plays right-handed. Schulenburg stands 183 cm (6 ft 0 in) tall.
This page tracks Jeffrey Von Der Schulenburg's upcoming schedule, latest results, recent form and surface record, with each match linking through to a detailed head-to-head and pre-match analysis. Scores update live as matches are played.
Rankings
Ranking Projection
Trajectory from our weekly snapshots. Defending— points dropping in the next ~12 weeks (last year's results at the same events). Win … — points gained by winning the round they're currently in. Expected — most likely landing rank from our draw model (Elo over the bracket). ATP points table.
Career highs
Ranking trajectory from our weekly snapshots (last ~12 months); peak rating and longest tour-level win streak from our match records. Umpiry rank is the player’s position by our rating — the arrow shows how many spots that is above (▲) or below (▼) their official ranking.
2026 season form
0–1W–L0%
Recent surface record
Career record
0–7W–L
Career surface record
Recent results
More Switzerland players
Explore the rankings
Frequently asked questions
How tall is Jeffrey Von Der Schulenburg?
Jeffrey Von Der Schulenburg is 183 cm (6 ft 0 in) tall.
When was Jeffrey Von Der Schulenburg born?
Jeffrey Von Der Schulenburg was born on 13 February 2002 (24 years old).
Where is Jeffrey Von Der Schulenburg from?
Jeffrey Von Der Schulenburg is from Switzerland.
Is Jeffrey Von Der Schulenburg right or left-handed?
Jeffrey Von Der Schulenburg plays right-handed.