Fernando Romboli vs Andrew Lauret — Brazil F20 Round of 32
Brazil F20 · ITF · Round of 32
2 — 0
Sets
Monday, 4 July 2011 ·
clay
BRAAndrew Lauret
Last 10 · pre-match
LLLLLWWLWL
Romboli F.6-3 6-1
Lauret A.
Romboli F.
662
Lauret A.
310
Fernando Romboli defeated Andrew Lauret 6-3 6-1 in the Brazil F20 round of 32 on clay. The result followed the form book — Fernando Romboli came in leading the head-to-head 1–0. Fernando Romboli extended the head-to-head to 2–0.
Key context
- Match story: Fernando Romboli dropped just 4 games past Andrew Lauret.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2010-12-20 | Brazil F38 | R16 | clay | Fernando Romboli | 6-2 |
Statistics
This seasonRomboli F.Lauret A.
1st serve in·
61%
—
1st serve points won·
67%
—
2nd serve points won·
46%
—
Service points won·
59%
—
Return points won·
35%
—
Break points saved·
53%
—
Aces / match·
3.6
—
Double faults / match·
3.6
—
Averages over each player's completed matches in the selected window. ATP, WTA & Challenger.