Paul Henri Mathieu defeated Florent Serra 6-0 7-6 7-6 in the Roland Garros round of 64 on clay. Paul Henri Mathieu extended the head-to-head to 3–2.
| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2007-10-08 | Moscow | QF | hard | Paul Henri Mathieu | 6-3 6-3 |
| 2006-10-02 | Metz | R16 | hard | Florent Serra | 1-6 6-3 7-6(2) |
| 2005-09-12 | Bucharest | QF | clay | Florent Serra | 6-3 6-1 |
| 2004-10-11 | Metz | R16 | hard | Paul Henri Mathieu | 7-6(5) 6-1 |
Each player's serve crossed against the other's return, converted to expected hold of serve. Recent completed matches, ATP, WTA & Challenger. About
Averages over each player's completed matches in the selected window (200 vs 200). ATP, WTA & Challenger.
Performance in the biggest moments — break points, deciding sets and tiebreaks (0–100, higher is better). About