Florent Serra defeated Paul Henri Mathieu 6-3 6-1 in the Bucharest quarter-final on clay. The upset overturned the form book — Paul Henri Mathieu came in leading the head-to-head 3–1, defending last year's quarter-final. Florent Serra narrowed the head-to-head to 3–2.
| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2007-10-08 | Moscow | QF | hard | Paul Henri Mathieu | 6-3 6-3 |
| 2006-10-02 | Metz | R16 | hard | Florent Serra | 1-6 6-3 7-6(2) |
| 2006-05-29 | Roland Garros | R64 | clay | Paul Henri Mathieu | 6-0 7-6(5) 7-6(6) |
| 2004-10-11 | Metz | R16 | hard | Paul Henri Mathieu | 7-6(5) 6-1 |
Each player's serve crossed against the other's return, converted to expected hold of serve. Recent completed matches, ATP, WTA & Challenger. About
Averages over each player's completed matches in the selected window (200 vs 200). ATP, WTA & Challenger.
Performance in the biggest moments — break points, deciding sets and tiebreaks (0–100, higher is better). About