UMPIRY

Andrei Mlendea vs Teodor Bolanu — Romania F18 Round of 16

Romania F18R16ClayMon 29 AugFinal
Andrei MlendeaROU
Teodor BolanuROU
SetsGames2
76
0
54

Andrei Mlendea defeated Teodor Bolanu 7-5 6-4 in the Romania F18 round of 16 on clay. The result followed the form book — Andrei Mlendea came in leading the head-to-head 1–0. Andrei Mlendea extended the head-to-head to 2–0.

Key context

  • Match story: Andrei Mlendea edged Teodor Bolanu in two tight sets (7–5 6–4).

How the match was decided

Auto-generated

Mlendea A. took it in straight sets.

Match statistics

Match statistics are not available for this match. They appear once the official scoring feed publishes them.

Common opponents

0 shared · last 12 months
No common opponents in the last 12 months. Surface form and ELO carry more weight here.

Head-to-head

2 meetings · Mlendea A. leads 2–0
20

Draw

Closing odds

Player context

Before the match
Mlendea A.Bolanu T.1 601ELO1 4471 606Clay ELO1 4536–4Last 100–10

Cite this

Andrei Mlendea beat Teodor Bolanu 7-5 6-4. Umpiry, "Andrei Mlendea vs Teodor Bolanu — Romania F18 Round of 16", https://umpiry.com/match/2005-08-29/bolanu-vs-mlendea-romania-f18-r16?utm_source=cite (as of 29 August 2005).