Andrei Mlendea defeated Teodor Bolanu 4-6 6-4 6-0 in the Romania F17 round of 32 on clay.
Mlendea A. came through in three sets.
Andrei Mlendea beat Teodor Bolanu 4-6 6-4 6-0. Umpiry, "Andrei Mlendea vs Teodor Bolanu — Romania F17 Round of 32", https://umpiry.com/match/2005-08-22/bolanu-vs-mlendea-romania-f17-r32?utm_source=cite (as of 22 August 2005).