Andrei Mlendea vs Teodor Bolanu — Romania F17 Round of 32

Romania F17R32ClayMon 22 AugFinal
Andrei MlendeaROU
Teodor BolanuROU
SetsGames2
466
1
640

Andrei Mlendea defeated Teodor Bolanu 4-6 6-4 6-0 in the Romania F17 round of 32 on clay.

Key context

  • Match story: Andrei Mlendea dropped the opening set before beating Teodor Bolanu 4–6 6–4 6–0.

How the match was decided

Auto-generated

Mlendea A. came through in three sets.

Match statistics

Match statistics are not available for this match. They appear once the official scoring feed publishes them.

Common opponents

0 shared · last 12 months
No common opponents in the last 12 months. Surface form and ELO carry more weight here.

Head-to-head

1 meeting · Mlendea A. leads 1–0
10
  • Mlendea A.August 2005Romania F17This matchClay4-6 6-4 6-0

Draw

Closing odds

Player context

Before the match
Mlendea A.Bolanu T.1 601ELO1 4471 606Clay ELO1 4536–4Last 100–10

Cite this

Andrei Mlendea beat Teodor Bolanu 4-6 6-4 6-0. Umpiry, "Andrei Mlendea vs Teodor Bolanu — Romania F17 Round of 32", https://umpiry.com/match/2005-08-22/bolanu-vs-mlendea-romania-f17-r32?utm_source=cite (as of 22 August 2005).