David Wheaton vs Guillaume Raoux — Wimbledon Round of 64
Wimbledon · ATP · Round of 64
3 — 0
Sets
Monday, 24 June 1996 ·
grass
Wheaton D.6-4 7-5 7-6
Raoux G.
Wheaton D.
67773
Raoux G.
45640
David Wheaton defeated Guillaume Raoux 6-4 7-5 7-6 in the Wimbledon round of 64 on grass. The result followed the form book — David Wheaton came in leading the head-to-head 1–0, defending last year's round of 32. David Wheaton extended the head-to-head to 2–0.
Key context
- Match story: David Wheaton edged Guillaume Raoux in three tight sets (6–4 7–5 7–6).
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1996-05-27 | Roland Garros | R128 | clay | David Wheaton | 6-7(3) 6-0 6-4 6-4 |
Statistics
This season1st serve in·Slight edge
60%
55%
1st serve points won·Even
71%
72%
2nd serve points won·Slight edge
47%
53%
Service points won·Even
61%
64%
Return points won·Even
37%
35%
Break points saved·Even
63%
61%
Aces / match·Clear edge
6.1
4.5
Double faults / match·Dominant
5.0
2.9
Averages over each player's completed matches in the selected window (39 vs 133). ATP, WTA & Challenger.
Conditions
Court speed
Medium-fastrewards aggression
SlowFast