David Wheaton vs Guillaume Raoux — Roland Garros Round of 128
Roland Garros · ATP · Round of 128
3 — 1
Sets
Monday, 27 May 1996 ·
clay
Wheaton D.6-7 6-0 6-4 6-4
Raoux G.
Wheaton D.
636663
Raoux G.
770441
David Wheaton defeated Guillaume Raoux 6-7 6-0 6-4 6-4 in the Roland Garros round of 128 on clay. The result followed the form book — David Wheaton came in leading the head-to-head 1–0, defending last year's round of 32. David Wheaton extended the head-to-head to 2–0.
Key context
- Match story: David Wheaton dropped the opening set before beating Guillaume Raoux 6–7 6–0 6–4 6–4.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1996-06-24 | Wimbledon | R64 | grass | David Wheaton | 6-4 7-5 7-6(4) |
Statistics
This season1st serve in·Slight edge
60%
55%
1st serve points won·Even
71%
72%
2nd serve points won·Slight edge
47%
53%
Service points won·Even
61%
64%
Return points won·Even
37%
35%
Break points saved·Even
63%
61%
Aces / match·Clear edge
6.1
4.5
Double faults / match·Dominant
5.0
2.9
Averages over each player's completed matches in the selected window (39 vs 133). ATP, WTA & Challenger.
Conditions
Court speed
Slowlow bounce, long rallies
SlowFast