Byron Black vs Henrik Holm — Australian Open Round of 128
Australian Open · ATP · Round of 128
3 — 0
Sets
Monday, 15 January 1996 ·
hard
Black B.6-3 6-2 6-4
Holm H.
Black B.
6663
Holm H.
3240
Byron Black defeated Henrik Holm 6-3 6-2 6-4 in the Australian Open round of 128 on hard. The result followed the form book — Byron Black came in leading the head-to-head 1–0, defending last year's round of 128. Byron Black extended the head-to-head to 2–0.
Key context
- Match story: Byron Black closed it out in three sets, 6–3 6–2 6–4.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1994-07-18 | Washington | R16 | hard | Byron Black | 7-6(7) 6-4 |
Statistics
This season1st serve in·Slight edge
61%
50%
1st serve points won·Slight edge
68%
78%
2nd serve points won·Slight edge
51%
45%
Service points won·Even
62%
62%
Return points won·Even
40%
36%
Break points saved·Even
60%
58%
Aces / match·Dominant
3.8
10.1
Double faults / match·Dominant
2.3
10.7
Averages over each player's completed matches in the selected window (200 vs 7). ATP, WTA & Challenger.
Conditions
Court speed
Fastbig serves, short points
SlowFast