Byron Black vs Henrik Holm — Washington Round of 16
Washington · ATP · Round of 16
2 — 0
Sets
Monday, 18 July 1994 ·
hard
Black B.7-6 6-4
Holm H.
Black B.
7962
Holm H.
6740
Byron Black defeated Henrik Holm 7-6 6-4 in the Washington round of 16 on hard. The result followed the form book — Byron Black came in leading the head-to-head 1–0, defending last year's round of 64. Byron Black extended the head-to-head to 2–0.
Key context
- Match story: Byron Black edged Henrik Holm in two tight sets (7–6 6–4).
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1996-01-15 | Australian Open | R128 | hard | Byron Black | 6-3 6-2 6-4 |
Statistics
This season1st serve in·Slight edge
61%
50%
1st serve points won·Slight edge
68%
78%
2nd serve points won·Slight edge
51%
45%
Service points won·Even
62%
62%
Return points won·Even
40%
36%
Break points saved·Even
60%
58%
Aces / match·Dominant
3.8
10.1
Double faults / match·Dominant
2.3
10.7
Averages over each player's completed matches in the selected window (200 vs 7). ATP, WTA & Challenger.
Conditions
Court speed
Fastbig serves, short points
SlowFast