Alexander Rozin advanced to the M15 Fayetteville quarterfinals by defeating Hoyoung Roh 7-6, 6-4. Rozin hit 8 aces and had a 82% first-serve win percentage, while Roh had 1 ace and 100% break points converted. Rozin converted 33% of his break points and had 2 service breaks to Roh's 1.
Generated automatically from Umpiry match data.
Rozin A. took it in straight sets, breaking once in each.
Break of serve
Alexander Rozin beat Hoyoung Roh 7-6(5) 6-4. Umpiry, "Alexander Rozin vs Hoyoung Roh — M15 Fayetteville Quarter-final", https://umpiry.com/match/2026-10-02/roh-vs-rozin-m15-fayetteville-qf?utm_source=cite (as of 2 October 2026).