Pedro Albuquerque Dietrich vs Pedro Sakamoto — M15 Leme Round of 16
Pedro Sakamoto advanced to the quarterfinals of the M15 Leme tournament with a 6-3, 6-4 victory over Pedro Albuquerque Dietrich in the Round of 16. Sakamoto hit 0 aces and 1 double fault, while Dietrich hit 2 aces and 6 double faults. Sakamoto converted 50% of his break points and won 4 service breaks, compared to Dietrich's 0 service breaks and 100% break point conversion.
Generated automatically from Umpiry match data.
Key context
- Match story: Pedro Sakamoto closed it out in two sets, 6–3 6–4.
How the match was decided
Auto-generatedSakamoto P. took it in straight sets.
- 1st-serve points wonSakamoto P. 69% · Albuquerque Dietrich P. 72%
- AcesSakamoto P. 0 · Albuquerque Dietrich P. 2
- Double faultsSakamoto P. 1 · Albuquerque Dietrich P. 6
Match momentum
Whole matchAlbuquerque Dietrich P.Sakamoto P.Late momentumSakamoto P.27
5Last 12 points7
9Last 3 games12
0/0Break points2/2
Break of serve
Common opponents
0 shared · last 12 monthsNo common opponents in the last 12 months. Surface form and ELO carry more weight here.
Head-to-head
2 meetings · Sakamoto P. leads 2–002
- Sakamoto P.September 2026M15 LemeThis matchClay3-6 4-6
- Sakamoto P.October 2025M25 Lajeado 1Clay6-3 6-1
Draw
Closing odds
Next up
Player context
Before the matchAlbuquerque Dietrich P.Sakamoto P.1 501ELO1 6891 500Clay ELO1 6684–5Last 109–118Age33
Cite this
Pedro Sakamoto beat Pedro Albuquerque Dietrich 3-6 4-6. Umpiry, "Pedro Albuquerque Dietrich vs Pedro Sakamoto — M15 Leme Round of 16", https://umpiry.com/match/2026-09-10/dietrich-vs-sakamoto-m15-leme-r16?utm_source=cite (as of 10 September 2026).