UMPIRY
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Andrea Colombo vs Fabrizio Andaloro — M25 Pozzuoli Round of 16

Fabrizio Andaloro defeated Andrea Colombo 6-2, 6-1 in the Round of 16 at the M25 Pozzuoli tournament. Andaloro did not hit an ace but converted one of three break points, while securing one service break to advance. Colombo hit one ace and also committed one double fault in the match.

Generated automatically from Umpiry match data.

Key context

How the match was decided

Auto-generated

Andaloro F. took it in straight sets, breaking twice in each.

  • Breaks of serveAndaloro F. 4 · Colombo A. 0
  • 1st-serve points wonAndaloro F. 88% · Colombo A. 50%
  • AcesAndaloro F. 0 · Colombo A. 1

Turning points

When the match moved
  1. Set 11–3BreakAndaloro F. · Broke, never broken back
  2. Set 12–6SetAndaloro F. · Broke to take the set
  3. Set 21–3BreakAndaloro F. · Broke, never broken back
Serve flowColombo A. broken 4 times · Andaloro F. unbroken.
  • Hold to love/15
  • Hold to 30
  • Hold to 40 / deuce
  • Broken
  • Result unknown
Colombo A.
3/7Andaloro F.
8/8
Set 1Set 2

Match momentum

Whole matchColombo A.Andaloro F.
EvenColombo A.Andaloro F.
Late momentumAndaloro F.83
4Last 12 points8
7Last 3 games14
0/0Break points4/7

Break of serve

Match statistics

Colombo A.Andaloro F.
Serve
  • 1Aces0
  • 1Double faults1
  • 50%1st serve points won88%
  • 43% · 3/7Service games held100% · 8/8
Return
  • 0%Break points won33%
  • 0Breaks of serve4

Common opponents

0 shared · last 12 months
No common opponents in the last 12 months. Surface form and ELO carry more weight here.

Head-to-head

1 meeting · Andaloro F. leads 1–0
01

Draw

Closing odds

Player context

Before the match
Colombo A.Andaloro F.1 566ELO1 6621 558Hard ELO1 6535–5Last 105–523Age25Career $19K2026 $9KEarningsCareer $88K2026 $11K

Match info

  • Started12:22 local

Cite this

Fabrizio Andaloro beat Andrea Colombo 2-6 1-6. Umpiry, "Andrea Colombo vs Fabrizio Andaloro — M25 Pozzuoli Round of 16", https://umpiry.com/match/2026-09-10/andaloro-vs-colombo-m25-pozzuoli-r16?utm_source=cite (as of 10 September 2026).