Chan Yeong Oh vs Yusuke Takahashi — M15 Maanshan 7 Round of 16
JPN5
Yeong Oh C.
Yusuke Takahashi defeated Chan Yeong Oh in the Round of 16 at the M15 Maanshan 7. The match ended with a score of 6-2, 6-1 in favor of Takahashi. Takahashi served 8 aces and won 96% of his first-serve points, converting 56% of break points, while Oh converted 100% of his break points but only won 55% of first-serve points.
Generated automatically from Umpiry match data.
Key context
- Match story: Yusuke Takahashi dropped just 3 games past Chan Yeong Oh.
Head to head
0–2| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2026-08-27 | M15 Maanshan | R16 | hard | Yusuke Takahashi | 2-6 2-6 |
| 2016-06-09 | Japan F7 | QF | hard | Yusuke Takahashi | 6-1 6-0 |
Statistics
This seasonAverages over each player's completed matches in the selected window. ATP, WTA & Challenger.
Win Probability
Pre-match · updated 04:50 UTC50–58%
58–67%
67–80%
80%+
Clear favourite · Takahashi Y. clearly ahead, but no certainty
Calibrated model (out-of-sample validated). Probability is a statistical estimate, not a certainty. How it works.
Umpiry Score
Pre-matchThe Umpiry Score combines match-context factors — matchup, form, fatigue, travel and motivation — into a single 0–10 score, updated daily. Read how it works.