Johan Alexander Rodriguez Rodriguez vs E. Strode — M15 Huamantla 4 Round of 16
E. Strode defeated Johan Alexander Rodriguez Rodriguez in the Round of 16 at the M15 Huamantla 4. The match ended with a score of 6-7, 7-6, 6-2 in favor of E. Strode. E. Strode hit 8 aces and 7 double faults, while Johan Alexander Rodriguez Rodriguez had 0 aces and 4 double faults.
Generated automatically from Umpiry match data.
Key context
- Match story: E. Strode dropped the opening set before beating Johan Alexander Rodriguez Rodriguez 6–7 7–6 6–2.
How the match was decided
Auto-generatedStrode E. came through in three sets.
- AcesStrode E. 8 · Rodriguez J. 0
- Double faultsStrode E. 7 · Rodriguez J. 4
Serve & return performance
Key performance gapsAcesStrode E. served 8 aces, Rodriguez J. 0. Largest performance gap of the match.+8Rodriguez J.0Strode E.8
Double faultsRodriguez J. served 4 double faults, Strode E. 7.+3Rodriguez J.4Strode E.7
Common opponents
0 shared · last 12 monthsNo common opponents in the last 12 months. Surface form and ELO carry more weight here.
Head-to-head
1 meeting · Strode E. leads 1–001
- Strode E.July 2026M15 Huamantla 4This matchHard7-6(2) 6-7(6) 2-6
Draw
Closing odds
Player context
Before the matchRodriguez J.Strode E.1 606ELO1 5101 541Hard ELO1 5105–5Last 103–222Age24
Cite this
E. Strode beat Johan Alexander Rodriguez Rodriguez 7-6(2) 6-7(6) 2-6. Umpiry, "Johan Alexander Rodriguez Rodriguez vs E. Strode — M15 Huamantla 4 Round of 16", https://umpiry.com/match/2026-07-30/rodriguez-vs-strode-m15-huamantla-4-r16?utm_source=cite (as of 30 July 2026).