Anastasia Kulikova vs Thea Frodin — W75 Lexington Round of 32
Kulikova A.
Anastasia Kulikova defeated Thea Frodin in the Round of 32 at the W75 Lexington tournament, coming back from a set down to win 4-6, 6-2, 6-3. Kulikova hit 2 aces and 4 double faults, while Frodin hit 5 aces and 14 double faults. Kulikova converted 45% of break points and won 5 service breaks, compared to Frodin's 38% conversion rate and 3 service breaks.
Generated automatically from Umpiry match data.
Key context
- Match story: Anastasia Kulikova dropped the opening set before beating Thea Frodin 4–6 6–2 6–3.
Head to head
No previous meetings on record.
Statistics
This seasonAverages over each player's completed matches in the selected window (33 vs 18). ATP, WTA & Challenger.
Win Probability
Pre-match · updated 17:50 UTC50–58%
58–67%
67–80%
80%+
Clear favourite · Kulikova A. clearly ahead, but no certainty
Calibrated model (out-of-sample validated). Probability is a statistical estimate, not a certainty. How it works.
Umpiry Score
Pre-matchThe Umpiry Score combines match-context factors — matchup, form, fatigue, travel and motivation — into a single 0–10 score, updated daily. Read how it works.
Freshness
Recent loadKulikova A.: 2 days rest · 2 matches, 41 games (7d) · Frodin T.: 21 days rest. Higher means fresher. About