L. Talan Lopatic vs Rares Teodor Pieleanu — M15 Bucharest 2 Round of 32
M15 Bucharest 2 · ITF · Round of 32
2 — 1
Sets
Tuesday, 7 July 2026 ·
clay
Talan Lopatic L.6-0 3-6 6-1
Teodor Pieleanu R.
Talan Lopatic L.
6362
Teodor Pieleanu R.
0611
L. Talan Lopatic defeated Rares Teodor Pieleanu in the Round of 32 of the M15 Bucharest 2 tournament on clay, winning 6-0, 3-6, 6-1. Lopatic hit one ace and one double fault, while Pieleanu had no aces and eight double faults. Lopatic converted 62% of his break points and won five service breaks to Pieleanu's two.
Key context
- Match story: L. Talan Lopatic handed Rares Teodor Pieleanu a first-set bagel in a 6–0 3–6 6–1 win.
Head to head
No previous meetings on record.
Umpiry Score
Pre-match6.1
Even matchUmpiry ScorePartial · surface data limited5.7
Slight disadvantageUmpiry ScorePartial · surface data limitedForm & Matchup
5.0No prior meetings
H2H5.0No prior meetings
Context
5.0Didn't play here last year
Defending pts5.0Didn't play here last year
The Umpiry Score combines match-context factors — matchup, form, fatigue, travel and motivation — into a single 0–10 score, updated daily. Read how it works.
Conditions
Weather
29°CMainly clear
Wind 2 km/hHumidity 34%