Tianhui Zhang vs Grigoriy Lomakin — M15 Wuning 4 Round of 16
Tianhui Zhang defeated Grigoriy Lomakin 6-3, 2-6, 6-4 in the Round of 16 at the M15 Wuning 4. The match saw Zhang and Lomakin convert an equal number of service breaks, three each. Zhang had 2 aces and 8 double faults, while Lomakin had 4 aces and 2 double faults.
Generated automatically from Umpiry match data.
Key context
- Match story: Tianhui Zhang closed it out in three sets, 6–3 2–6 6–4.
How the match was decided
Auto-generatedZhang T. came through in three sets.
- AcesZhang T. 2 · Lomakin G. 4
- Double faultsZhang T. 8 · Lomakin G. 2
Serve & return performance
Key performance gapsDouble faultsLomakin G. served 2 double faults, Zhang T. 8. Largest performance gap of the match.+6Zhang T.8Lomakin G.2
Common opponents
0 shared · last 12 monthsNo common opponents in the last 12 months. Surface form and ELO carry more weight here.
Draw
Closing odds
Next up
Player context
Before the matchZhang T.Lomakin G.1 558ELO1 4911 543Hard ELO1 4896–4Last 105–520Age28Career $35K2026 $9KEarningsCareer $144K2026 $6K
Cite this
Tianhui Zhang beat Grigoriy Lomakin 6-3 2-6 6-4. Umpiry, "Tianhui Zhang vs Grigoriy Lomakin — M15 Wuning 4 Round of 16", https://umpiry.com/match/2026-07-02/lomakin-vs-zhang-m15-wuning-4-r16?utm_source=cite (as of 2 July 2026).