Jahnie Van Zyl vs Polina Leykina — W15 Hillcrest Round of 16
Polina Leykina defeated Jahnie Van Zyl in the Round of 16 at the W15 Hillcrest tournament, winning 6-3, 5-7, 6-3 on hard courts. Leykina and Van Zyl each hit one ace, with Leykina committing five double faults to Van Zyl's two. Leykina won 57% of her first serves and converted 44% of break points, while Van Zyl converted 67% of break points; Leykina secured 7 service breaks to Van Zyl's 6.
Generated automatically from Umpiry match data.
Key context
- Match story: Polina Leykina closed it out in three sets, 6–3 5–7 6–3.
How the match was decided
Auto-generatedLeykina P. came through in three sets.
- AcesLeykina P. 1 · Van Zyl J. 1
- Double faultsLeykina P. 5 · Van Zyl J. 2
Serve & return performance
Key performance gapsDouble faultsVan Zyl J. served 2 double faults, Leykina P. 5. Largest performance gap of the match.+3Van Zyl J.2Leykina P.5
Common opponents
0 shared · last 12 monthsNo common opponents in the last 12 months. Surface form and ELO carry more weight here.
Head-to-head
1 meeting · Leykina P. leads 1–001
- Leykina P.July 2026W15 HillcrestThis matchHard3-6 7-5 3-6
Draw
Closing odds
Next up
Player context
Before the matchVan Zyl J.Leykina P.1 556ELO1 6071 534Hard ELO1 5848–2Last 104–617Age31RightPlaysRightCareer $10K2026 $4KEarningsCareer $192K2026 $11K
Cite this
Polina Leykina beat Jahnie Van Zyl 3-6 7-5 3-6. Umpiry, "Jahnie Van Zyl vs Polina Leykina — W15 Hillcrest Round of 16", https://umpiry.com/match/2026-07-02/leykina-vs-zyl-w15-hillcrest-r16?utm_source=cite (as of 2 July 2026).