Jiri Lehecka defeated Alex Molcan in the Round of 64 at Wimbledon, winning in straight sets 6-3, 6-2, 6-4. Lehecka hit 25 aces to Molcan's 3 and converted 75% of his break points, compared to Molcan's 22%. Lehecka won 79% of his first-serve points and broke Molcan's serve six times.
Generated automatically from Umpiry match data.
Lehecka J. took it in straight sets, with six breaks of serve.
Break of serve
Lehecka J. and Molcan A. faced 1 of the same opponent in the last 12 months. Lehecka J. went 0–1 (0%) against them, Molcan A. 0–1 (0%).
Only 1 common opponent — too few for any conclusion. Shown without assessment.
Jiri Lehecka beat Alex Molcan 6-3 6-2 6-4. Umpiry, "Jiri Lehecka vs Alex Molcan — Wimbledon Round of 64", https://umpiry.com/match/2026-07-02/lehecka-vs-molcan-wimbledon-r64?utm_source=cite (as of 2 July 2026).