Alan Fernando Rubio Fierros vs Johan Alexander Rodriguez Rodriguez — M15 Huamantla 2 Quarter-final

M15 Huamantla 2 · ITF · Quarter-final
MEX
Alan Fernando Rubio Fierros
#631ATP
27 yrs · 175 cm · Right-handed
Last 10 · pre-match
LLLWLWWLLL
2 — 1
Sets
Friday, 26 July 2024 ·
hard
COL
Johan Alexander Rodriguez Rodriguez
#660ATP
1411ELO
1389Hard ELO
22 yrs · 173 cm · Right-handed
Last 10 · pre-match
LWLLLLWWWW
Rubio Fierros A.
6-3 2-6 6-4
Alexander Rodriguez Rodriguez J.
Rubio Fierros A.
6262
Alexander Rodriguez Rodriguez J.
3641

Alan Fernando Rubio Fierros defeated Johan Alexander Rodriguez Rodriguez 6-3 2-6 6-4 in the M15 Huamantla 2 quarter-final on hard.

Key context

Head to head

No previous meetings on record.

Statistics

This season
Rubio Fierros A.Alexander Rodriguez Rodriguez J.
1st serve in·Even
66%
62%
1st serve points won·Even
65%
69%
2nd serve points won·Slight edge
46%
52%
Service points won·Even
59%
62%
Return points won·Even
41%
41%
Break points saved·Even
59%
60%
Aces / match·Even
2.2
2.7
Double faults / match·Clear edge
3.8
3.0

Averages over each player's completed matches in the selected window (87 vs 70). ATP, WTA & Challenger.

Draw