UMPIRY
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Areg Stepanian vs Hod Cohen — M15 Benicarlo 1 Qualifying Round of 64

M15 Benicarlo 1Q64QualifyingClaySun 6 NovFinal
Areg StepanianARG
Hod CohenISR
SetsGames2
66
0
11

Areg Stepanian defeated Hod Cohen 6-1 6-1 in the M15 Benicarlo 1 qualifying round of 64 on clay.

Key context

  • Match story: Areg Stepanian dropped just 2 games past Hod Cohen.

How the match was decided

Auto-generated

Stepanian A. took it in straight sets.

Match statistics

Match statistics are not available for this match. They appear once the official scoring feed publishes them.

Common opponents

0 shared · last 12 months
No common opponents in the last 12 months. Surface form and ELO carry more weight here.

Head-to-head

1 meeting · Stepanian A. leads 1–0
10

Draw

Closing odds

Player context

Before the match
Stepanian A.Cohen H.1 350ELO1 4811 397Clay ELO1 4952–8Last 100–322Age20

Cite this

Areg Stepanian beat Hod Cohen 6-1 6-1. Umpiry, "Areg Stepanian vs Hod Cohen — M15 Benicarlo 1 Qualifying Round of 64", https://umpiry.com/match/2022-11-06/cohen-vs-stepanian-m15-benicarlo-1-q64?utm_source=cite (as of 6 November 2022).