Kei Nishikori vs Alex De Minaur — Rotterdam Round of 16
Nishikori K.
Kei Nishikori defeated Alex De Minaur 6-3 2-6 7-5 in the Rotterdam round of 16 on hard. The upset overturned the form book — Alex De Minaur came in ranked #6, leading the head-to-head 1–0. Kei Nishikori claimed a first win over Alex De Minaur in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Kei Nishikori closed it out in three sets, 6–3 2–6 7–5.
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2019-08-26 | US Open | R32 | hard | Alex De Minaur | 6-2 6-4 2-6 6-3 |
Serve vs return
This seasonEach player's serve crossed against the other's return, converted to expected hold of serve. Recent completed matches, ATP, WTA & Challenger. About
Serve & return on hard
Per-surface Serve / Return Rating (0–100, percentile within the hard field, opponent-adjusted over 52 weeks). About
Statistics
This seasonAverages over each player's completed matches in the selected window (116 vs 200). ATP, WTA & Challenger.
Clutch
Under pressurePerformance in the biggest moments — break points, deciding sets and tiebreaks (0–100, higher is better). About
Freshness
Recent loadDe Minaur A.: 5 days rest · 2 matches, 72 games (7d). Higher means fresher. About