
Alexander Zverev defeated Pierre Hugues Herbert 2-6 6-4 7-6 4-6 6-4 in the Roland Garros round of 64 on clay. The result followed the form book — Alexander Zverev came in ranked #2, defending last year's quarter-final. Alexander Zverev extended the head-to-head to 2–1.
| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2016-05-23 | Roland Garros | R128 | clay | Alexander Zverev | 5-7 6-2 7-6(6) 7-5 |
| 2015-01-04 | Brisbane | Q1 | hard | Pierre Hugues Herbert | 7-6(2) 6-4 |
Each player's serve crossed against the other's return, converted to expected hold of serve. Recent completed matches, ATP, WTA & Challenger. About
Per-surface Serve / Return Rating (0–100, percentile within the clay field, opponent-adjusted over 52 weeks). About
Averages over each player's completed matches in the selected window (199 vs 200). ATP, WTA & Challenger.
Performance in the biggest moments — break points, deciding sets and tiebreaks (0–100, higher is better). About
Zverev A.: 2 days rest · 4 matches, 148 games (7d) · Herbert P.: 3 days rest · 1 match, 39 games (7d). Higher means fresher. About