Alexandre Muller vs Peter Polansky — Roland Garros Qualifying Round of 64
Alexandre Muller defeated Peter Polansky 6-2 4-6 7-6 in the Roland Garros qualifying round of 64 on clay. The upset overturned the form book — Peter Polansky came in defending last year's round of 128.
Key context
- Match story: Alexandre Muller closed it out in three sets, 6–2 4–6 7–6.
How the match was decided
Auto-generatedMuller A. came through in three sets.
Common opponents
1 shared · last 12 monthsMuller A. and Polansky P. faced 1 of the same opponent in the last 12 months. Muller A. went 1–0 (100%) against them, Polansky P. 0–1 (0%).
1–0100%Muller A. · better vs 1Record vs common opponents0–10%Polansky P. · better vs 0
Vs common opponents · derived from scorelines
2–0Sets1–2
13–9Games14–14
1–0Tiebreaks0–0
0–0Deciding sets0–1
Only 1 common opponent — too few for any conclusion. Shown without assessment.
vs Young D.#552W7-6 6-3Roland Garros · clayL5-7 6-1 3-6US Open · hard
Head-to-head
1 meeting · Muller A. leads 1–010
- Muller A.May 2019Roland GarrosThis matchClay6-2 4-6 7-6(2)
Draw
Closing odds
Player context
Before the matchMuller A.Polansky P.1 832ELO1 6091 726Clay ELO1 5516–4Last 102–822Age30183 cmHeight180 cmRightPlaysRight
Cite this
Alexandre Muller beat Peter Polansky 6-2 4-6 7-6(2). Umpiry, "Alexandre Muller vs Peter Polansky — Roland Garros Qualifying Round of 64", https://umpiry.com/match/2019-05-22/muller-vs-polansky-roland-garros-q64?utm_source=cite (as of 22 May 2019).