Andrej Martin vs Jordan Thompson — Nanchang CH Final

Nanchang CH · CHALLENGER · Final
SVK
Andrej Martin
#392ATP
1470ELO
1444Clay ELO
36 yrs · 183 cm · Right-handed
Last 10 · pre-match
WWLLWWLWWL
2 — 1
Sets
Monday, 22 April 2019
clay
Jordan Thompson
AUS1
Jordan Thompson
#309ATP
1772ELO
1605Clay ELO
$153kYTD
$9.6MCAREER
32 yrs · 183 cm · Right-handed
Last 10 · pre-match
LWLWWLWWLW
Martin A.
6-4 1-6 6-3
Thompson J.
Martin A.
6162
Thompson J.
4631

Andrej Martin defeated Jordan Thompson 6-4 1-6 6-3 in the Nanchang CH final on clay. The upset overturned the form book — Jordan Thompson came in ranked #309, defending last year's semi-final.

Key context

  • Match story: Andrej Martin closed it out in three sets, 6–4 1–6 6–3.

Head to head

No previous meetings on record.

Serve vs return

This season
Martin A.serving70% hold

wins 58% of points on serve vs Thompson J.

Thompson J.serving74% hold

wins 60% of points on serve vs Martin A.

Serve advantage — Thompson J.

Each player's serve crossed against the other's return, converted to expected hold of serve. Recent completed matches, ATP, WTA & Challenger. About

Statistics

This season
Martin A.Thompson J.
1st serve in·Even
62%
60%
1st serve points won·Slight edge
65%
74%
2nd serve points won·Slight edge
49%
54%
Service points won·Slight edge
59%
66%
Return points won·Slight edge
42%
37%
Break points saved·Slight edge
58%
63%
Aces / match·Dominant
2.6
7.2
Double faults / match·Dominant
3.0
1.3

Averages over each player's completed matches in the selected window (200 vs 199). ATP, WTA & Challenger.

Clutch

Under pressure
Martin A.Thompson J.
Clutch Rating·Dominant
12
70
Break points saved·Dominant
54
97
Break points won·Even
25
24
Deciding sets·Dominant
23
91
Tiebreaks·Dominant
9
95

Performance in the biggest moments — break points, deciding sets and tiebreaks (0–100, higher is better). About

Conditions

Court speed
Medium-slowfavours grinders
SlowFast
Final
Martin A.
Thompson J.[1]
6-41-66-3
Semi-finals
Thompson J.[1]
Ramanathan R.[4]
7-626-3
Martin A.
Milojevic N.[7]
6-06-4
Quarter-finals
Thompson J.[1]
Soeda G.[11]
6-746-46-3
Ramanathan R.[4]
Zhang Z.
6-36-0
Milojevic N.[7]
Harris A.
6-24-66-0
Martin A.
Patael B.
6-27-5
R16
Milojevic N.[7]
Santillan A.
7-627-65
Harris A.
Pavlasek A.[13]
6-34-66-3
Thompson J.[1]
Safranek V.
6-26-1
Martin A.
Oliveira G.
6-46-2
Patael B.
Clarke J.[12]
6-37-5
Zhang Z.
Lopez Perez E.[8]
6-26-4
Ramanathan R.[4]
Uchida K.[16]
6-26-3
Soeda G.[11]
Duckworth J.[5]
7-56-1
R32
Ramanathan R.[4]
Te R.
6-36-2
Zhang Z.
Janvier M.[10]
7-652-1
Safranek V.
Ignatik U.[15]
7-666-4
Uchida K.[16]
Gabashvili T.
6-42-66-3
Harris A.
Vardhan V.
6-26-3
Pavlasek A.[13]
Chung Y.
6-36-2
Santillan A.
Nedovyesov A.[9]
6-44-67-5
Milojevic N.[7]
Mukund S.
6-26-4
Clarke J.[12]
Purcell M.
7-626-3
Patael B.
Kubler J.[6]
6-14-67-5
Duckworth J.[5]
Wu D.
7-696-3
Soeda G.[11]
Balaji N.
6-46-4
Thompson J.[1]
Grills J.
6-34-66-1
Lopez Perez E.[8]
Ochi M.
6-36-0
Martin A.
Bolt A.[3]
6-26-4
Oliveira G.
Lee D.[14]
6-36-2
R64
Mukund S.
Tokuda R.
6-13-1
Santillan A.
Lo C.
6-16-2
Safranek V.
Wu H.
3-66-16-3
Gabashvili T.
Xia Z.
6-27-5
Purcell M.
He Y.
7-626-2
Patael B.
Gao X.
6-16-4
Balaji N.
Bai Y.
2-66-27-64
Chung Y.
Noguchi R.
6-46-3
Oliveira G.
Banes M.
6-46-3
Grills J.
Saville L.
6-36-4
Harris A.
Margaroli L.
6-16-2
Martin A.
Lamasine T.
6-26-2
Te R.
Sun F.
6-46-4
Ochi M.
Wu T.
6-36-2
Zhang Z.
Myneni S.
6-46-4
Wu D.
Cui J.
6-16-2