Astra Sharma vs Shelby Rogers — Bogota Round of 32
Bogota · WTA · Round of 32
2 — 1
Sets
Monday, 8 April 2019
clay
Sharma A.
66662
Rogers S.
37811
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2019-05-27 | Roland Garros | R128 | clay | Shelby Rogers | 6-3 6-3 |
Statistics
Recent form59%1st serve in+2%57%
63%1st serve points won+1%64%
46%2nd serve points won46%
56%Service points won56%
40%Return points won+1%39%
52%Break points saved+1%51%
2.7Aces / match2.7
3.1Double faults / match+0.22.9
Averages from each player's recent completed matches (20 vs 20). ATP, WTA & Challenger.
Draw
Quarter-finals
Sharma A.
Errani S.
6-17-5
Arruabarrena L.[11]
Zidansek T.[5]
6-46-2
Anisimova A.[6]
Osorio C.
6-21-66-3
Haddad Maia B.
Sorribes Tormo S.[7]
6-766-26-3
R16
Errani S.
Schoofs B.
6-26-1
Arruabarrena L.[11]
Paolini J.
7-646-1
Haddad Maia B.
Schmiedlova A.[4]
7-637-66
Zidansek T.[5]
Vickery S.
6-26-0
Sorribes Tormo S.[7]
Bogdan A.
6-44-66-4
Osorio C.
Ahn K.
6-46-766-3
Anisimova A.[6]
Lepchenko V.
6-46-4
Sharma A.
Linette M.[8]
6-46-3
R32
Sorribes Tormo S.[7]
Mchale C.
6-46-4
Errani S.
Bara I.
4-66-26-3
Schoofs B.
Arango E.
6-26-4
Linette M.[8]
Bolsova A.
2-67-656-0
Bogdan A.
Paquet C.
6-26-776-2
Schmiedlova A.[4]
Bonaventure Y.
6-26-4
Ahn K.
Ostapenko J.[1]
2-67-657-5
Lepchenko V.
Kostova E.
6-36-1
Anisimova A.[6]
Lisicki S.
4-66-36-2
Paolini J.
Di Lorenzo F.
6-23-66-4
Osorio C.
Perrin C.
6-46-4
Zidansek T.[5]
Khromacheva I.
4-66-16-4
Haddad Maia B.
Siegemund L.
6-27-5
Sharma A.
Rogers S.
6-36-766-1
Vickery S.
Kuwata H.
6-46-2
Arruabarrena L.[11]
Babos T.
6-776-46-1