Radu Albot vs Lukas Lacko — Indian Wells Masters Qualifying Round 2
Indian Wells Masters · ATP · Qualifying Round 2
2 — 0
Sets
Monday, 4 March 2019 ·
hard
Albot R.7-6 7-6
Lacko L.
Albot R.
772
Lacko L.
660
Radu Albot defeated Lukas Lacko 7-6 7-6 in the Indian Wells Masters qualifying round 2 on hard. The result followed the form book — Radu Albot came in leading the head-to-head 2–0, defending last year's round of 128. Radu Albot extended the head-to-head to 3–0.
Key context
- Match story: Radu Albot won all two sets in tiebreaks against Lukas Lacko.
Head to head
2–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2021-03-15 | Dubai | Q1 | hard | Radu Albot | 3-6 6-4 6-4 |
| 2021-03-13 | Dubai | Q32 | hard | Radu Albot | 3-6 6-4 6-4 |
Statistics
This season1st serve in·Even
64%
60%
1st serve points won·Slight edge
66%
72%
2nd serve points won·Even
49%
49%
Service points won·Even
60%
63%
Return points won·Slight edge
40%
35%
Break points saved·Even
60%
60%
Aces / match·Dominant
2.0
6.7
Double faults / match·Slight edge
2.9
2.5
Averages over each player's completed matches in the selected window (199 vs 129). ATP, WTA & Challenger.
Conditions
Court speed
Medium-slowfavours grinders
SlowFast