Radu Albot vs Lukas Lacko — Indian Wells Masters Qualifying Round 2
Radu Albot defeated Lukas Lacko 7-6 7-6 in the Indian Wells Masters qualifying round 2 on hard. The result followed the form book — Radu Albot came in leading the head-to-head 1–0, defending last year's round of 128. Radu Albot extended the head-to-head to 2–0.
Key context
- Match story: Radu Albot won all two sets in tiebreaks against Lukas Lacko.
How the match was decided
Auto-generatedAlbot R. took it in straight sets.
Common opponents
1 shared · last 12 monthsAlbot R. and Lacko L. faced 1 of the same opponent in the last 12 months. Albot R. went 0–1 (0%) against them, Lacko L. 0–1 (0%).
0–10%Albot R. · better vs 0Record vs common opponents0–10%Lacko L. · better vs 0
Vs common opponents · derived from scorelines
0–2Sets0–3
7–12Games10–19
Only 1 common opponent — too few for any conclusion. Shown without assessment.
vs Pospisil V.L3-6 4-6Chengdu · hardL5-7 3-6 2-6US Open · hard
Head-to-head
2 meetings · Albot R. leads 2–020
- Albot R.March 2019Indian Wells MastersThis matchHard7-6 7-6
- Albot R.October 2014Geneva CHHard5-1
Draw
Closing odds
Player context
Before the matchAlbot R.Lacko L.1 712ELO1 6151 653Hard ELO1 5657–3Last 102–829Age31175 cmHeight185 cmRightPlaysRight
Cite this
Radu Albot beat Lukas Lacko 7-6 7-6. Umpiry, "Radu Albot vs Lukas Lacko — Indian Wells Masters Qualifying Round 2", https://umpiry.com/match/2019-03-04/albot-vs-lacko-indian-wells-masters-q2?utm_source=cite (as of 4 March 2019).