Carlos Berlocq vs Juan Ignacio Londero — Bastad CH Round of 16
Bastad CH · CHALLENGER · Round of 16
2 — 1
Sets
Monday, 9 July 2018
clay
Berlocq C.
37762
Londero J.
66141
Head to head
1–2| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2019-04-08 | Marrakech | R32 | clay | Juan Ignacio Londero | 6-2 6-4 |
| 2018-07-02 | Marburg CH | QF | clay | Juan Ignacio Londero | 6-1 6-4 |
| 2018-04-02 | Panama City CH | SF | clay | Carlos Berlocq | 6-7(3) 7-5 7-6(1) |
Statistics
Recent form69%1st serve in+5%64%
71%1st serve points won+6%65%
53%2nd serve points won+6%47%
65%Service points won+7%58%
38%Return points won38%
58%Break points saved+6%52%
3.3Aces / match+1.41.9
2.2Double faults / match+0.93.1
Averages from each player's recent completed matches (20 vs 20). ATP, WTA & Challenger.
Draw
Quarter-finals
Horansky F.
Rosol L.
6-36-1
Ymer M.
Berlocq C.
6-14-67-5
Moutet C.[3]
Lestienne C.
7-56-3
Martinez P.
Safranek V.
7-56-2
R16
Safranek V.
Wu D.
1-66-46-2
Moutet C.[3]
Oliveira G.
6-43-66-2
Berlocq C.
Londero J.
3-67-616-4
Horansky F.
Harris L.
7-666-4
Ymer M.
Hemery C.[6]
6-43-66-2
Martinez P.
Monteiro T.[4]
6-46-4
Lestienne C.
Ignatik U.
6-16-4
Rosol L.
Andreozzi G.[1]
6-45-77-64
R32
Horansky F.
Nagal S.
6-20-0
Ignatik U.
Okala J.
7-674-0
Monteiro T.[4]
Klein L.
6-47-64
Lestienne C.
Auger Aliassime F.[7]
6-43-2
Londero J.
Ymer E.[2]
6-16-4
Rosol L.
Tatlot J.
6-36-2
Safranek V.
Bergevi F.
6-30-67-5
Oliveira G.
Mridha J.
6-47-5
Hemery C.[6]
Eriksson M.
6-46-1
Wu D.
Otte O.[8]
6-26-4
Martinez P.
Blancaneaux G.
6-46-1
Andreozzi G.[1]
Collarini A.
2-66-46-2
Moutet C.[3]
Zhang Z.
6-26-4
Berlocq C.
Nedelko I.
6-36-0
Ymer M.
Kolar Z.
6-31-66-0
Harris L.
Laaksonen H.[5]
6-46-4