Carlos Berlocq vs Juan Ignacio Londero — Panama City CH Semi-final
Panama City CH · CHALLENGER · Semi-final
2 — 1
Sets
Monday, 2 April 2018
clay
Berlocq C.
637772
Londero J.
775611
Head to head
1–2| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2019-04-08 | Marrakech | R32 | clay | Juan Ignacio Londero | 6-2 6-4 |
| 2018-07-09 | Bastad CH | R16 | clay | Carlos Berlocq | 3-6 7-6(1) 6-4 |
| 2018-07-02 | Marburg CH | QF | clay | Juan Ignacio Londero | 6-1 6-4 |
Statistics
Recent form69%1st serve in+5%64%
71%1st serve points won+6%65%
53%2nd serve points won+6%47%
65%Service points won+7%58%
38%Return points won38%
58%Break points saved+6%52%
3.3Aces / match+1.41.9
2.2Double faults / match+0.93.1
Averages from each player's recent completed matches (20 vs 20). ATP, WTA & Challenger.
Draw
Quarter-finals
Londero J.
Choinski J.
6-36-1
Rola B.
Hanfmann Y.[3]
3-66-46-4
Berlocq C.[4]
Hernandez J.
7-56-2
Collarini A.
Rodriguez C.
6-47-67
R16
Londero J.
Pavic A.
6-46-4
Hernandez J.
Krueger M.[8]
6-33-66-4
Choinski J.
Clarke J.
6-46-2
Collarini A.
Song E.
7-630-0
Berlocq C.[4]
Basso A.
6-26-4
Hanfmann Y.[3]
Bagnis F.
6-26-4
Rodriguez C.
Olivo R.[6]
6-37-65
Rola B.
Torebko P.
6-36-2
R32
Clarke J.
Krstin P.
7-56-2
Olivo R.[6]
Munoz de la Nava D.
6-46-4
Basso A.
Sakamoto P.
6-26-2
Hernandez J.
Gomez E.
2-66-27-5
Rola B.
Opelka R.[7]
6-36-1
Rodriguez C.
Koepfer D.
6-44-66-4
Pavic A.
King D.[5]
6-16-4
Bagnis F.
Nedelko I.
7-676-2
Hanfmann Y.[3]
Statham J.
6-45-76-3
Berlocq C.[4]
Coria F.
6-46-1
Torebko P.
Korda S.
6-27-64
Krueger M.[8]
Quiroz R.
6-33-66-4
Choinski J.
Mantilla F.
6-746-46-2
Song E.
Dutra Silva R.[2]
3-66-46-4
Collarini A.
Arguello F.
3-66-17-62
Londero J.
Gomez J.
6-26-1