Lenny Hampel vs Bogdan Ionut Apostol — Italy F4 Round of 16
Italy F4 · ITF · Round of 16
2 — 0
Sets
Monday, 19 March 2018 ·
clay
Hampel L.7-6 7-6
Ionut Apostol B.
Hampel L.
78772
Ionut Apostol B.
66640
Lenny Hampel defeated Bogdan Ionut Apostol 7-6 7-6 in the Italy F4 round of 16 on clay. The result followed the form book — Lenny Hampel came in leading the head-to-head 2–0. Lenny Hampel extended the head-to-head to 3–0.
Key context
- Match story: Lenny Hampel won all two sets in tiebreaks against Bogdan Ionut Apostol.
Head to head
2–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2021-07-23 | M25 Kottingbrunn 1 | QF | clay | Lenny Hampel | 6-1 4-6 7-5 |
| 2014-12-01 | Turkey F43 | Q32 | hard | Lenny Hampel | 7-5 2-6 7-6(4) |
Statistics
This season1st serve in·Even
56%
56%
1st serve points won·Slight edge
75%
70%
2nd serve points won·Even
48%
44%
Service points won·Even
63%
59%
Return points won·Even
31%
35%
Break points saved·Even
61%
58%
Aces / match·Clear edge
4.9
3.4
Double faults / match·Even
3.0
2.7
Averages over each player's completed matches in the selected window (7 vs 14). ATP, WTA & Challenger.