Yannick Jankovits vs Jakob Sude — Greece F10 Qualifying Round
Greece F10 · ITF · Qualifying Round
2 — 0
Sets
Monday, 20 November 2017 ·
hard
Jankovits Y.6-3 6-3
Sude J.
Jankovits Y.
662
Sude J.
330
Yannick Jankovits defeated Jakob Sude 6-3 6-3 in the Greece F10 qualifying round on hard. Yannick Jankovits extended the head-to-head to 2–1.
Key context
- Match story: Yannick Jankovits dropped just 6 games past Jakob Sude.
Head to head
1–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2017-02-27 | Italy F2 | R16 | carpet | Yannick Jankovits | 7-6(4) 6-3 |
| 2010-09-27 | France F16 | R32 | carpet | Jakob Sude | 6-3 7-6(4) |
Statistics
This season1st serve in·Slight edge
56%
64%
1st serve points won·Slight edge
69%
62%
2nd serve points won·Even
48%
44%
Service points won·Even
59%
56%
Return points won·Even
39%
43%
Break points saved·Even
55%
51%
Aces / match·Clear edge
3.4
1.3
Double faults / match·Dominant
3.8
2.1
Averages over each player's completed matches in the selected window (33 vs 16). ATP, WTA & Challenger.