Alex De Minaur defeated Roberto Ortega Olmedo 6-1 6-3 in the Portugal F11 semi-final on hard. The upset overturned the form book — Roberto Ortega Olmedo came in leading the head-to-head 1–0. Alex De Minaur claimed a first win over Roberto Ortega Olmedo in two meetings, narrowing the head-to-head to 1–1.
| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2016-04-18 | Spain F10 | QF | clay | Roberto Ortega Olmedo | 6-4 6-4 |
Averages over each player's completed matches in the selected window (200 vs 146). ATP, WTA & Challenger.
Each player's serve crossed against the other's return, converted to expected hold of serve. Recent completed matches, ATP, WTA & Challenger. About
Per-surface Serve / Return Rating (0–100, percentile within the hard field, opponent-adjusted over 52 weeks). About