Filip Krajinovic vs John Patrick Smith — Heilbronn CH Qualifying Round 2
Heilbronn CH · CHALLENGER · Qualifying Round 2
2 — 0
Sets
Monday, 15 May 2017
clay
Krajinovic F.
672
Smith J.
150
Head to head
1–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2017-08-28 | US Open | Q2 | hard | John Patrick Smith | 6-4 6-4 |
| 2015-03-12 | Indian Wells Masters | Q1 | hard | Filip Krajinovic | 6-7(3) 6-3 7-6(3) |
Statistics
Recent form68%1st serve in+2%70%
65%1st serve points won+1%64%
49%2nd serve points won+3%46%
60%Service points won+2%58%
38%Return points won+5%33%
55%Break points saved55%
3.2Aces / match+1.64.8
1.4Double faults / match+0.60.8
Averages from each player's recent completed matches (20 vs 4). ATP, WTA & Challenger.
Draw — qualifying
Q3
Stebe C.
Bachinger M.
6-13-67-65
Koepfer D.
Fanselow S.
7-636-4
Krajinovic F.
Otte O.
6-46-0
Groth S.[2]
Reuter Y.[6]
6-33-66-4
Q2
Stebe C.
Wu D.
3-66-37-5
Otte O.
Cervantes Huegun I.[1]
7-56-2
Groth S.[2]
Griekspoor T.
6-37-65
Bachinger M.
Zampieri C.
6-46-3
Reuter Y.[6]
Lazov A.
6-36-3
Fanselow S.
Klahn B.
7-57-65
Krajinovic F.
Smith J.
6-17-5
Koepfer D.
Ojeda Lara R.
6-36-4
Q1
Groth S.[2]
Puetz T.
7-656-1
Smith J.
Boehler D.
7-57-5
Griekspoor T.
Nys H.
7-676-3
Otte O.
Ofner S.
6-33-66-2
Koepfer D.
Marcora R.
6-06-2
Reuter Y.[6]
Kern R.
7-646-1
Ojeda Lara R.
Velotti A.[4]
6-36-0
Lazov A.
Bednarek T.
6-36-1
Stebe C.
Kekez D.
2-66-06-3
Krajinovic F.
Masur D.[5]
6-36-2
Bachinger M.
Wessels L.
7-626-2
Wu D.
Arevalo M.[7]
6-46-4
Klahn B.
Zapata Miralles B.
7-656-1
Zampieri C.
Safranek V.[3]
6-37-62
Fanselow S.
Donati M.[8]
7-636-4