Radu Albot vs Alex De Minaur — Indian Wells Masters Qualifying Round 2
Albot R.
Radu Albot defeated Alex De Minaur 6-3 3-6 6-4 in the Indian Wells Masters qualifying round 2 on hard. The upset overturned the form book — Alex De Minaur came in ranked #5. Radu Albot extended the head-to-head to 2–0.
Key context
- Match story: Radu Albot closed it out in three sets, 6–3 3–6 6–4.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2017-03-06 | Indian Wells Masters | Q2 | hard | Radu Albot | 6-3 3-6 6-4 |
Serve vs return
This seasonEach player's serve crossed against the other's return, converted to expected hold of serve. Recent completed matches, ATP, WTA & Challenger. About
Serve & return on hard
Per-surface Serve / Return Rating (0–100, percentile within the hard field, opponent-adjusted over 52 weeks). About
Statistics
This seasonAverages over each player's completed matches in the selected window (199 vs 200). ATP, WTA & Challenger.
Clutch
Under pressurePerformance in the biggest moments — break points, deciding sets and tiebreaks (0–100, higher is better). About
Freshness
Recent loadAlbot R.: 9 days rest · 2 matches (14d) · De Minaur A.: 8 days rest · 4 matches (14d). Higher means fresher. About