Radu Albot vs Henri Laaksonen — Prague CH Quarter-final
Albot R.
Radu Albot defeated Henri Laaksonen 6-3 6-2 in the Prague CH quarter-final on clay. The upset overturned the form book — Henri Laaksonen came in leading the head-to-head 1–0, but Radu Albot had been the form player, winning 5 of their last 9 on clay. Radu Albot claimed a first win over Henri Laaksonen in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Radu Albot dropped just 5 games past Henri Laaksonen.
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2016-02-08 | Memphis | Q2 | hard | Henri Laaksonen | 6-7(6) 7-6(4) 6-1 |
Serve vs return
This seasonEach player's serve crossed against the other's return, converted to expected hold of serve. Recent completed matches, ATP, WTA & Challenger. About
Statistics
This seasonAverages over each player's completed matches in the selected window (199 vs 200). ATP, WTA & Challenger.
Clutch
Under pressurePerformance in the biggest moments — break points, deciding sets and tiebreaks (0–100, higher is better). About
Freshness
Recent loadAlbot R.: 9 days rest · 2 matches (14d). Higher means fresher. About