Christopher Heyman vs Jeroen Vanneste — Netherlands F2 Qualifying Round of 16
Netherlands F2 · ITF · Qualifying Round of 16
2 — 1
Sets
Monday, 20 June 2016 ·
clay
Heyman C.7-5 3-6 7-6
Vanneste J.
Heyman C.
737102
Vanneste J.
56681
Christopher Heyman defeated Jeroen Vanneste 7-5 3-6 7-6 in the Netherlands F2 qualifying round of 16 on clay. The result followed the form book — Christopher Heyman came in leading the head-to-head 1–0. Christopher Heyman extended the head-to-head to 2–0.
Key context
- Match story: Christopher Heyman closed it out in three sets, 7–5 3–6 7–6.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2013-07-08 | Belgium F4 | R16 | clay | Christopher Heyman | 6-4 6-2 |
Statistics
This season1st serve in·Clear edge
70%
57%
1st serve points won·Even
66%
69%
2nd serve points won·Even
51%
47%
Service points won·Even
62%
60%
Return points won·Even
40%
42%
Break points saved·Even
60%
56%
Aces / match·Even
2.8
2.7
Double faults / match·Dominant
2.0
4.3
Averages over each player's completed matches in the selected window (200 vs 131). ATP, WTA & Challenger.