Yannick Jankovits vs Peter Kobelt — Israel F4 Semi-final
Israel F4 · ITF · Semi-final
2 — 0
Sets
Monday, 7 March 2016 ·
hard
Jankovits Y.7-6 7-6
Kobelt P.
Jankovits Y.
77772
Kobelt P.
64630
Yannick Jankovits defeated Peter Kobelt 7-6 7-6 in the Israel F4 semi-final on hard. The result followed the form book — Yannick Jankovits came in leading the head-to-head 1–0. Yannick Jankovits extended the head-to-head to 2–0.
Key context
- Match story: Yannick Jankovits won all two sets in tiebreaks against Peter Kobelt.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2014-06-02 | Israel F7 | SF | hard | Yannick Jankovits | 6-3 6-1 |
Statistics
This season1st serve in·Slight edge
57%
62%
1st serve points won·Even
70%
74%
2nd serve points won·Even
50%
51%
Service points won·Even
61%
65%
Return points won·Slight edge
42%
36%
Break points saved·Slight edge
57%
62%
Aces / match·Dominant
2.9
9.1
Double faults / match·Slight edge
2.9
3.4
Averages over each player's completed matches in the selected window (101 vs 109). ATP, WTA & Challenger.