Grigor Dimitrov vs Paul Henri Mathieu — Rotterdam Round of 32
BUL5
Dimitrov G.
Grigor Dimitrov defeated Paul Henri Mathieu 4-6 7-6 6-2 in the Rotterdam round of 32 on hard. The upset overturned the form book — Paul Henri Mathieu came in leading the head-to-head 1–0, defending last year's round of 16. Grigor Dimitrov claimed a first win over Paul Henri Mathieu in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Grigor Dimitrov dropped the opening set before beating Paul Henri Mathieu 4–6 7–6 6–2.
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2012-10-22 | Basel | QF | hard | Paul Henri Mathieu | 7-6(2) 7-6(4) |
Serve vs return
This seasonEach player's serve crossed against the other's return, converted to expected hold of serve. Recent completed matches, ATP, WTA & Challenger. About
Statistics
This seasonAverages over each player's completed matches in the selected window (200 vs 145). ATP, WTA & Challenger.
Clutch
Under pressurePerformance in the biggest moments — break points, deciding sets and tiebreaks (0–100, higher is better). About
Freshness
Recent loadDimitrov G.: 8 days rest · 4 matches (14d). Higher means fresher. About