Yannik Reuter vs Leon Schutt — Tunisia F7 Round of 32
Tunisia F7 · ITF · Round of 32
2 — 0
Sets
Monday, 10 November 2014 ·
hard
Reuter Y.6-2 6-0
Schutt L.
Reuter Y.
662
Schutt L.
200
Yannik Reuter defeated Leon Schutt 6-2 6-0 in the Tunisia F7 round of 32 on hard. The result followed the form book — Yannik Reuter came in leading the head-to-head 1–0. Yannik Reuter extended the head-to-head to 2–0.
Key context
- Match story: Yannik Reuter handed Leon Schutt a second-set bagel in a 6–2 6–0 win.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2013-07-01 | Germany F8 | R16 | clay | Yannik Reuter | 6-4 6-2 |
Statistics
This season1st serve in·Even
61%
63%
1st serve points won·Even
66%
64%
2nd serve points won·Even
49%
48%
Service points won·Even
59%
58%
Return points won·Even
40%
40%
Break points saved·Slight edge
54%
59%
Aces / match·Even
2.3
2.8
Double faults / match·Even
2.5
2.5
Averages over each player's completed matches in the selected window (143 vs 36). ATP, WTA & Challenger.