Yannick Jankovits vs Alexios Halebian — Turkey F29 Qualifying Round
Turkey F29 · ITF · Qualifying Round
2 — 1
Sets
Monday, 25 August 2014 ·
hard
Jankovits Y.2-6 6-3 6-2
Halebian A.
Jankovits Y.
2662
Halebian A.
6321
Yannick Jankovits defeated Alexios Halebian 2-6 6-3 6-2 in the Turkey F29 qualifying round on hard. The result followed the form book — Yannick Jankovits came in leading the head-to-head 1–0. Yannick Jankovits extended the head-to-head to 2–0.
Key context
- Match story: Yannick Jankovits dropped the opening set before beating Alexios Halebian 2–6 6–3 6–2.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2014-08-18 | Turkey F28 | QF | hard | Yannick Jankovits | 6-2 6-7(5) 6-1 |
Statistics
This season1st serve in·Even
57%
60%
1st serve points won·Even
69%
70%
2nd serve points won·Even
50%
49%
Service points won·Even
61%
61%
Return points won·Slight edge
42%
37%
Break points saved·Slight edge
57%
65%
Aces / match·Clear edge
2.9
5.1
Double faults / match·Even
2.8
3.0
Averages over each player's completed matches in the selected window (109 vs 73). ATP, WTA & Challenger.