Yannick Jankovits vs Alexios Halebian — Turkey F28 Qualifying Round
Turkey F28 · ITF · Qualifying Round
2 — 1
Sets
Monday, 18 August 2014 ·
hard
Jankovits Y.6-2 6-7 6-1
Halebian A.
Jankovits Y.
66562
Halebian A.
27711
Yannick Jankovits defeated Alexios Halebian 6-2 6-7 6-1 in the Turkey F28 qualifying round on hard. The result followed the form book — Yannick Jankovits came in leading the head-to-head 1–0. Yannick Jankovits extended the head-to-head to 2–0.
Key context
- Match story: Yannick Jankovits came through a tight passage before pulling clear — 6–2 6–7 6–1.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2014-08-25 | Turkey F29 | QF | hard | Yannick Jankovits | 2-6 6-3 6-2 |
Statistics
This season1st serve in·Slight edge
56%
61%
1st serve points won·Even
67%
69%
2nd serve points won·Even
47%
48%
Service points won·Even
58%
61%
Return points won·Even
39%
37%
Break points saved·Slight edge
56%
61%
Aces / match·Dominant
3.0
6.4
Double faults / match·Even
3.3
3.3
Averages over each player's completed matches in the selected window (54 vs 29). ATP, WTA & Challenger.