Joao Pedro Sorgi vs Fernando Romboli — Brazil F7 Round of 32
Brazil F7 · ITF · Round of 32
2 — 0
Sets
Monday, 11 August 2014 ·
clay
Sorgi J.7-5 6-1
Romboli F.
Sorgi J.
762
Romboli F.
510
Joao Pedro Sorgi defeated Fernando Romboli 7-5 6-1 in the Brazil F7 round of 32 on clay. The upset overturned the form book — Fernando Romboli came in leading the head-to-head 3–0. Joao Pedro Sorgi claimed a first win over Fernando Romboli in four meetings, narrowing the head-to-head to 3–1.
Key context
- Match story: Joao Pedro Sorgi came through a tight passage before pulling clear — 7–5 6–1.
Head to head
0–3| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2013-10-21 | Brazil F13 | QF | hard | Fernando Romboli | 6-3 6-1 |
| 2013-09-23 | Brazil F9 | R32 | hard | Fernando Romboli | 6-7(2) 7-5 6-4 |
| 2012-05-14 | Brazil F10 | F | clay | Fernando Romboli | 6-3 6-4 |
Statistics
This season1st serve in·Even
62%
61%
1st serve points won·Even
68%
66%
2nd serve points won·Slight edge
51%
46%
Service points won·Even
61%
59%
Return points won·Slight edge
41%
35%
Break points saved·Even
57%
54%
Aces / match·Even
3.1
3.6
Double faults / match·Clear edge
2.6
3.6
Averages over each player's completed matches in the selected window (200 vs 117). ATP, WTA & Challenger.