UMPIRY
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Teodor Leahu vs Vlad Corneliu Pop — Romania F11 Qualifying Round of 32

Romania F11Q32QualifyingClayMon 11 AugFinal
Teodor LeahuROU
Vlad Corneliu PopROU
SetsGames2
636
1
362

Teodor Leahu defeated Vlad Corneliu Pop 6-3 3-6 6-2 in the Romania F11 qualifying round of 32 on clay.

Key context

  • Match story: Teodor Leahu closed it out in three sets, 6–3 3–6 6–2.

How the match was decided

Auto-generated

Leahu T. came through in three sets.

Match statistics

Match statistics are not available for this match. They appear once the official scoring feed publishes them.

Common opponents

0 shared · last 12 months
No common opponents in the last 12 months. Surface form and ELO carry more weight here.

Head-to-head

1 meeting · Leahu T. leads 1–0
10
  • Leahu T.August 2014Romania F11This matchClay6-3 3-6 6-2

Draw

Closing odds

Player context

Before the match
Leahu T.Corneliu Pop V.1 503ELO1 3931 503Clay ELO1 3943–7Last 102–8

Cite this

Teodor Leahu beat Vlad Corneliu Pop 6-3 3-6 6-2. Umpiry, "Teodor Leahu vs Vlad Corneliu Pop — Romania F11 Qualifying Round of 32", https://umpiry.com/match/2014-08-11/leahu-vs-pop-romania-f11-q32?utm_source=cite (as of 11 August 2014).