Teodor Leahu vs Vlad Corneliu Pop — Romania F11 Q32
Romania F11 · ITF · Q32
ROUTeodor Leahu
Last 10 · pre-match
LLWLLLWLLW
2 — 1
Sets
Monday, 11 August 2014 ·
clay
ROUVlad Corneliu Pop
Last 10 · pre-match
LLLLWLLWLL
Leahu T.6-3 3-6 6-2
Corneliu Pop V.
Leahu T.
6362
Corneliu Pop V.
3621
Teodor Leahu defeated Vlad Corneliu Pop 6-3 3-6 6-2 in the Romania F11 q32 on clay.
Key context
- Match story: Teodor Leahu closed it out in three sets, 6–3 3–6 6–2.
Head to head
No previous meetings on record.