Claudio Mircea vs Teodor Leahu — Romania F10 Qualifying Round of 32
Claudio Mircea defeated Teodor Leahu 7-6 7-6 in the Romania F10 qualifying round of 32 on clay. The upset overturned the form book — Teodor Leahu came in leading the head-to-head 2–0, but Claudio Mircea had been the form player, winning 3 of their last 6 on clay. Claudio Mircea claimed a first win over Teodor Leahu in three meetings, narrowing the head-to-head to 2–1.
Key context
- Match story: Claudio Mircea won all two sets in tiebreaks against Teodor Leahu.
How the match was decided
Auto-generatedMircea C. took it in straight sets.
Common opponents
0 shared · last 12 monthsNo common opponents in the last 12 months. Surface form and ELO carry more weight here.
Head-to-head
3 meetings · Leahu T. leads 2–112
- Mircea C.July 2014Romania F10This matchClay7-6(4) 7-6(4)
- Leahu T.June 2013Romania F5Clay6-2 6-2
- Leahu T.May 2013Romania F3Clay6-2 6-2
Draw
Closing odds
Player context
Before the matchMircea C.Leahu T.1 437ELO1 5031 444Clay ELO1 5034–6Last 103–7
Cite this
Claudio Mircea beat Teodor Leahu 7-6(4) 7-6(4). Umpiry, "Claudio Mircea vs Teodor Leahu — Romania F10 Qualifying Round of 32", https://umpiry.com/match/2014-07-28/leahu-vs-mircea-romania-f10-q32?utm_source=cite (as of 28 July 2014).